
How to Derive and Verify the Taylor Series Expansion for log (1+x)?
Sep 17, 2011 · How to Derive and Verify the Taylor Series Expansion for log (1+x)? uppaladhadium Sep 17, 2011 Expansion
How to Derive the Taylor Series for log (x)? - Physics Forums
Jun 18, 2019 · Hi, I was trying to solve the following problem myself but couldn't figure out how the given Taylor series for log (x) is found. Taylor series for a...
Log(x) do you assume base 10 or base e? • Physics Forums
Jul 28, 2014 · The discussion centers on the ambiguity of the logarithm notation "log(x)" and whether it should be assumed to be base 10 or base e. Many participants noted that in academic contexts, …
SOLUTION: solve: log x^2= (log x)^2 - Algebra Homework Help
You can put this solution on YOUR website! log (x^2) = (logx)^2,,,,remember loga^b=b*log a . 2logx = logx * logx . 2 logx -logx*logx =0 . factor . If 2a-a^2=0,, we ...
Determine whether a logarithmic function is odd or even
Jan 19, 2019 · Determine whether a logarithmic function is odd or even YoungPhysicist Jan 19, 2019 even Function Log Logarithmic
Understanding Why ln (x) and e Cancel Out • Physics Forums
Aug 4, 2012 · Hi, I have a hard time understanding why ln (x) and e cancel out, when, for example, we have something like: eln(2x+3) I tried an internet search but I did not get any good explanation, just …
Why do people refer ln (x) as log (x) ? • Physics Forums
Jul 28, 2011 · The discussion centers on the terminology surrounding logarithms, specifically why "ln (x)" is often referred to as "log (x)". Participants assert that in higher mathematics, particularly calculus, …
Log^2(x) and log(x)^2 are the same or not? - Physics Forums
Jan 5, 2007 · I hope to not seem to much silly but: log^2 (x) and log (x)^2 are the same or not? thanx
SOLUTION: log (9x+5)-log (x^ (2)-1)=1/2 - Algebra Homework Help
You can put this solution on YOUR website! log (9x+5)-log (x^ (2)-1)=1/2 place under single log log [ (9x+5)/ (x^2-1)]=1/2 convert to exponential form: 10^ (1/2)= (9x+5)/ (x^2-1)=√10 √10 (x^2-1)=9x+5 …
SOLUTION: x^logx = 100x - Algebra Homework Help
You can put this solution on YOUR website! your equation is: x^ (log (x)) = 100x divide both sides of this equation by x to get: (x^ (log (x))/x = 100 take the log of both sides of this equation to get: log (x^ (log …